The discontinuity are the point wherein the function is not defined.
The zeros are the points wherein f(x)=0.
Computing the discontinuity points:
Set [tex]x-1=0[/tex] then the discontinuity point is at [tex]x=1[/tex].
Comptine the zeroes:
Set [tex]3x^2+x-4=0[/tex]
Compute the discriminant: [tex]1^2-4(3)(-4)=49=7^2.[/tex]
Then with quadratic formula we get the solutions:
[tex](-1-7)/6=-8/6\\(-1+7)/6=1[/tex]
The two zeros are [tex]\dfrac{-8}{6},1[/tex]
