Let's assume
number of dimes in coin as 'd'
number of quarters in coin as 'q'
we are given
total number of coins is 16
so, we get
[tex] d+q=16 [/tex]
we know that
1 dime =$0.10
1 quarter=$0.25
we have
he has $2.20 in his pocket
so, we get equation as
[tex] 0.10d+0.25q=2.2 [/tex]
so, we get system of equation as
[tex] d+q=16 [/tex]
[tex] 0.10d+0.25q=2.2 [/tex]
Firstly, we will solve for q from first equation
[tex] q=16-d [/tex]
now, we can plug back q
[tex] 0.10d+0.25(16-d)=2.2 [/tex]
[tex] 0.10d+4-0.25d=2.2 [/tex]
[tex] -0.15d=-1.8 [/tex]
now, we can solve for d
[tex] d=12 [/tex]
now, we can solve for q
[tex] q=16-12 [/tex]
[tex] q=4 [/tex]
so,
number of dimes coins are 12
number of quarter coins are 4...........Answer