Sara is serving wings and burgers at her party. Wings cost $6.00 per serving and burgers are $3.00 each. Sara knows that at least 4 of her friends want wings. Sara must spend less than $45.00. If x represents the number of wing servings and y represents the number of burgers, which system of inequalities could be used to determine how many of each kind of food Sara can serve?

For this case we have the following variables:
x = the number of wing servings
y = the number of burgers
We write the system of equations:
"Sara knows that at least 4 of her friends want wings":
x> = 4
"Sara must spend less than $ 45.00":
6x + 3y <45
Answer:
Sara could use the following system of inequalities to determine how many of each kind of food She can serve:
6x + 3y <45x> = 4

Answer Link

FelisFelis FelisFelis · Answer 2 · 2019-12-18T06:51:32+01:00

Answer:

The required inequalities are [tex]x\geq 4[/tex] and [tex]6x+3y<45[/tex].

She can serve 4 wings and 6 burgers, so that she spend less than $45.

Step-by-step explanation:

Consider the provided information.

Wings cost $6.00 per serving and burgers are $3.00 each.

x represents the number of wing servings and y represents the number of burgers.

Sara knows that at least 4 of her friends want wings.

Thus [tex]x\geq 4[/tex]

Sara must spend less than $45.00

[tex]6x+3y<45[/tex]

Hence, the required inequalities are [tex]x\geq 4[/tex] and [tex]6x+3y<45[/tex].

Now find how many of each kind of food Sara can serve.

If she serve 4 wings:

[tex]6(4)+3y<45[/tex]

[tex]3y<45-24[/tex]

[tex]y<7[/tex]

She can serve 4 wings and 6 burgers, so that she spend less than $45.

Similarly, She can serve 5 wings and 4 burgers, she can serve 6 wings and 2 burger or she can serve 7 wings.