The combustion reaction for methane is as follows CH4 + 2O2 —> CO2 + 2H2O Stoichiometry of methane to CO2 is 1:1 Since oxygen is in excess, methane is the limiting reactant therefore amount of CO2 produced depends on methane reacted , Number of methane moles reacted = 136 g / 16 g/mol = 8.5 mol Therefore moles of CO2 to be produced = 8.5 mol Theoretically mass of CO2 to be produced = 8.5 mol x 44 g/mol = 374 g However actual yield = 353 g Percent yield = actual yield / theoretical yield x 100% Percent yield = 353 g/ 374 g x100% Percentage yield of CO2 = 94.4%
