wmatheis3623 wmatheis3623
  • 26-03-2018
  • Chemistry
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How many moles of pcl5 can be produced from 23.0 g of p4 (and excess cl2)?

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blahblahmali blahblahmali
  • 04-04-2018
The balanced equation for the above reaction is as follows
P4 + 10Cl2 —> 4PCl5
P4 is the limiting reactant. Stoichiometry of P4 to PCl5 is 1:4
The mass of P4 reacted = 23.0 g
Number of P4 moles = 23.0 g/ 124 g/mol = 0.185 mol
According to the stoichiometry the number of PCl5 moles produced are 4 times the amount of P4 moles reacted
Therefore PCl5 moles = 0.185 x 4 = 0.74 mol
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