Andrew can paint the neighbors house 6 times as fast as Bailey. the year Andrew and bailey worked together, it took them 5 days. how long would it take each to paint the house ?
Let Andrew be A and let Bailey be B Andrew is 6 times as quick as Bailey [tex]1a = 6b[/tex] When they worked together, it took them 5 days to paint the house. [tex]6b + 1b = 7b \\ 7b = 5days[/tex] If Bailey worked alone, she would take a much longer time [tex]5 \times 7 = 35days[/tex] Since Andrew is 6 times as quick as Bailey, [tex] \frac{(5 \times 7)}{6} = 5.8days[/tex] Andrew would take about 5.8 days while Bailey would take 35 days.
