Respuesta :

Catya
re-arrange the equation to standard form ax² + bx + c = 0

3x² - 4x + 10 = 0

a = 3
b = -4
c = 10

put these values into the quadratic formula..

[tex]x = \frac{-(-4) \ _+_/_-\ \sqrt{(-4)^2 - 4(3)(10)} }{2(3)} \\ \\ x = \frac{4 \ _+_/_- \ \sqrt{-104} }{6} \\ \\ x = \frac{2 \ _+/_- \ i\sqrt{26} }{3} [/tex]
kalosxash

Answer:

your answer would be

C. SIIIIIIMPLE

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