Answer:
6(3) - 4 + (3)^2
Explanation:
We are given that:
f(x) = 4-x^2
g(x) = 6x
First, we will compute (g-f)(x) as follows:
(g-f)(x) = 6x - (4-x^2) = 6x - 4 + x^2
Now, we will substitute with x=3 as follows:
(g-f)(3) = 6(3) - 4 + (3)^2
Hope this helps :)
