firesoccer5200 firesoccer5200
  • 23-02-2018
  • Mathematics
contestada

Find the dimensions of a rectangle whose area is 221 cm2 and whose perimeter is 60 cm. (enter your answers as a comma-separated list.)

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realtreegirl313
realtreegirl313 realtreegirl313
  • 23-02-2018
60 = 2 ( length + width ) 

30 = length + width 

Let length be = x and width = y 

x+y = 30 

xy = 209 

4xy = 836 

( x+ y)^2 = 900 

( x+y)^2 - 4xy = 900-836 = 64 

( x-y)^2 = 64 

x- y = 8 

x+y = 30 

ADD 2x =38 

x = 19 

y = 11 

ANSWER 19cm X 11cm
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