Tniyawilliata9 Tniyawilliata9
  • 26-01-2018
  • Mathematics
contestada

Solve for x in the equation x^2-8x+41=0

Respuesta :

manandhanteja manandhanteja
  • 28-01-2018
use quadratic formula

(-b +- (sqrt(b^2-4ac) ) / 2a


a=1
b=-8
c=41

1.

(8 + sqrt(64-4*1*41) ) / 2*1
4 + sqrt(-100) / 2
4 + 5i.......................... solution 1

2.

(8 - sqrt(64-4*1*41) ) / 2*1
4 - sqrt(-100) / 2
4 - 5i.......................... solution 2
Answer Link
shanmso2 shanmso2
  • 03-07-2018
x = [-(-8) +/- sqrt((-8)^2 -4*41)] / 2  

x =  ( 8 + sqrt (-100) / 2  and  (8 - sqrt(-100) / 2

 4 +or- 5i
Answer Link

Otras preguntas

Help please! Number 1 only. Due an hour later
Enzymes are not specific and can work on any compound anytime true or false
why do we need state, local, & federal laws
Carl collects coins compulsively, but he only likes quarters ($0.25) and dimes ($0.10). Carl currently has 125 coins for a total of $26.00. How many of each coi
High and low power distance cultures? Example
Which inequality is shown in the graph?
(5/8 x - 10) - (1/8 x - 12)
Which equation is not parallel to the graph of -8x = 5 - 4y through the point (0, -0.5)? 10x - 5y = 2.5 4x - 2y = 1 2x - y = 1 x - 0.5y = 0.25
Which of the following was NOT an advantage of the British army during the Revolutionary War
If log x (8x-3)-logx4=2, the value of x is or .