Respuesta :

[tex]\bf -1=5x^2-2x\implies 0=5x^2-2x+1 \\\\\\ \begin{array}{llccll} 0=&{{ 5}}x^2&{{ -2}}x&{{ +1}}\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array} \\\\\\ discriminant\implies b^2-4ac \implies (-2)^2-4(5)(1)[/tex]