yangyus
yangyus
22-08-2017
Mathematics
contestada
AP calculus HW Need help on #61
Respuesta :
coolstick
coolstick
23-08-2017
Expanding the limit, we get (x^2+2x∆x+∆x^2-2x-2∆x+1-x^2+2x-1)/
∆x
Crossing the 1s , the 2xs, and the x^2s out, we get
(2x
∆x+∆x^2-2∆x)/
∆x
Dividing the
∆x, we get
2x+
∆x-2.
Making the limit of
∆x=0, we get 2x-2.
Answer Link
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