ryanaguayo ryanaguayo
  • 24-07-2017
  • Mathematics
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What is the center of a circle given by the equation (x-3)2+(y-9)2=16

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jaybae2017
jaybae2017 jaybae2017
  • 24-07-2017
The answer is : y = - 1x + 28


how I did it


(x-3)2+(y-9)2=16


1x - 3 times 2 + 1y -9 times 2 = 16


1x - 6 + 1y -18 =16
      +6        +6

1x + 1y -12 = 16
             +12    +12

1x + 1y = 28
 -1x                -1x

1y = -1x + 28
/1       /1      /1

y = - 1x + 28 or y = - x + 28
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