lyndseyfrank2539 lyndseyfrank2539
  • 22-06-2017
  • Mathematics
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What are the coordinates of the vertex for f(x) = 2x2 + 4x + 9?

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jabberwock jabberwock
  • 22-06-2017
Your equation [tex]f(x)=2x^2+4x+9[/tex] is in the form [tex]y=ax^2+bx+c[/tex]
The vertex only relies on "a" and "b" though, so that +9 doesn't really matter in this case.  The vertex of a parabola is located where 
[tex]x=\frac{-b}{2a}=\frac{-4}{2(2)}=-1[/tex]
So your x-coordinate is -1.  You need to find f(-1) to find your y-coordinate, and then you list it in the form (-1, y).
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Nez
Nez Nez
  • 22-06-2017
Vertex: (-1,7)
Focus: (-1, 57 over 8)
Axis of Symmetry(AOS): x=-1
Directories: y= 55 over 8
X , Y
-3 , 15
-2 , 9
-1 , 7
0 , 9
1 , 5
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