Answer: d.20%growth
Step-by-step explanation:
The given function [tex]F(t)=50(1.2)^t[/tex] is similar to the exponential growth function [tex]y=A(1+r)^t[/tex], where A is the initial amount , r is the rate of growth and t is the time period.
In the given function A=50
[tex](1+r)=(1.2)\\\Rightarrow(1+r)=(1+0.2)\\\Rightarrow\ r=0.2\\\Rightarrow\r=0.2\times100\\\Rightarrow\ r=20\%[/tex]
Hence, in the given F(t), the rate of change = 20%growth.
