complete the equation for the linear function whose graph contains the points (-1,-2) and (3.10)
y+_=(x+1)

Question

25-03-2015
Mathematics

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complete the equation for the linear function whose graph contains the points (-1,-2) and (3.10)
y+_=(x+1)

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iGreen iGreen · Answer 1 · 2015-03-25T14:33:10+01:00

That's point-slope form:

y - y1 = m(x - x1)

Where y1 is the y-value of a point on the line, x1 is the x-value, and 'm' is the slope.

So let's find out what goes in the first blank.

As we can see, they replaced 'x1' with -1, and one of our points have an x-value of -1, that point is (-1, -2), this means y2 must be -2:

y + 2 = m(x + 1)

Now let's find the slope between the two points.

m = y2-y1/x2-x1

m = (10+2)/(3+1)

m = 12/4

m = 3

So the slope is 3, plug that in:

y + 2 = 3(x + 1)

complete the equation for the linear function whose graph contains the points (-1,-2) and (3.10) y+_______=______(x+1)

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Otras preguntas

complete the equation for the linear function whose graph contains the points (-1,-2) and (3.10)
y+_=(x+1)