gvldjayy
gvldjayy gvldjayy
  • 26-04-2017
  • Chemistry
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how much 6.0M HNO(small 3) is needed to neutralize 39mL of 2 M KOH

how much 60M HNOsmall 3 is needed to neutralize 39mL of 2 M KOH class=

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jstone0050
jstone0050 jstone0050
  • 26-04-2017
Equation of reaction 
KOH+HNO3--->KNO3+H2O 
CA=6.0M, CB=2.0M, VA=?, VB=39ml, na=1, nb=1 
CAVA/CBVB=na/nb 
6*VA/2*39=1/1 
6VA/78=1 
6VA=78 
VA=78/6. VA=13ml. 
VA=13ml.
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