The formula for pOH is -log(M), so we can plug in -log(0.0500), which gives us 1.3. However, KOH is a BASE, so we just solved for the pOH.
The formula for pH and pOH is ph + pOH = 14, so we need to subtract the 1.3 from 14 since we want the pH, not the pOH.
So, with that said, our final answer and pH is 12.7 :)
