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23-04-2017
Mathematics

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find A,B,C where 5x^2 + Ax -7 = B(x+2)^2 + C
where A,B,C are constants

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Аноним Аноним

23-04-2017

expanding the right side:-

5x^2 + Ax - 7 = Bx^2 +4Bx + 4B + C

Equating coefficients of x^2:-

B = 5

Equating coefficients of x:-

A = 4B
so
A = 4*5 = 20

Equating constants terms

-7 = 4B + C = 20 + C

C = - 27

A=20 , B = 5 and C = -27

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