leoncitaleon
leoncitaleon leoncitaleon
  • 22-02-2015
  • Mathematics
contestada

(2-3i)*(3+4i) perform following operations

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Аноним Аноним
  • 22-02-2015
[tex]\left( 2-3i \right) \left( 3+4i \right) \\ \\ =6+8i-9i-12{ i }^{ 2 }\\ \\ =6-i-12\left( -1 \right) \\ \\ =6-i+12\\ \\ =18-i[/tex]
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konrad509
konrad509 konrad509
  • 22-02-2015
[tex](2-3i)(3+4i)=\\ 6+8i-9i+12=\\ 18-i[/tex]
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