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23-02-2017
Chemistry

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Calculate the mass of oxygen released by the action of water on 10.0 grams of sodium peroxide (the other product is sodium hydroxide).

Respuesta :

scme1702 scme1702

01-03-2017

The reaction equation:
2H₂O + 2Na₂O₂ → 4NaOH + O₂

Moles of sodium peroxide = 10 / 78 = 0.128

Moles of oxygen released = 0.128 / 2 = 0.064 mol
Mass of oxygen = 0.064 x 32

Mass of oxygen = 2.05 grams

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