Given:
QT = x + 6
TR = x - 4
SR = 12
PS = 27
Hence;
[tex]\frac{12}{27}=\frac{x-4}{x+6}[/tex]
Solving for x:
[tex]\begin{gathered} 12(x+6)=27(x-4) \\ \\ 12x+72=27x-108 \\ \\ 12x-27x=-108-72 \\ \\ -15x=-180 \\ \\ x=12 \end{gathered}[/tex]
Replacing x on QT and TR:
QT = x + 6 = 12 + 6 = 18
TR = x - 4 = 12 - 4 = 8
ANSWER
QT = 18
TR = 8
