MeilanieP537305 MeilanieP537305
  • 26-10-2022
  • Mathematics
contestada

of stion Instructions: Use the ratio of a 45-45-90 triangle to solve for the variables. Leave your answers as radicals in simplest form. m 512 n 45° N т n =

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AlonzoG46390 AlonzoG46390
  • 26-10-2022

From the diagram, we can see that

[tex]\begin{gathered} \sin \text{ 45 = }\frac{m}{5\sqrt[]{2}} \\ \frac{1}{\sqrt[]{2}}\text{ = }\frac{m}{5\sqrt[]{2}} \\ 1\text{ = }\frac{m}{5} \\ m\text{ = 1 x 5 = 5} \end{gathered}[/tex][tex]\begin{gathered} \cos \text{ 45 = }\frac{n}{5\sqrt[]{2}} \\ \frac{1}{\sqrt[]{2}}\text{ = }\frac{n}{5\sqrt[]{2}} \\ 1\text{ = }\frac{n}{5} \\ n\text{ = 1 x 5 = 5} \end{gathered}[/tex]

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