So,
We want to solve the operation:
[tex](\frac{(20+21^2-\frac{116874}{9})}{\frac{20}{3}\cdot12-\frac{21}{(\frac{116874}{9})}})^{-1}[/tex]We could rewrite this expression as:
[tex](\frac{20+441-12986}{80-\frac{21}{12986}})^{-1}[/tex]And, this is:
[tex](\frac{-12525}{\frac{1038859}{12986}})^{-1}=-\frac{1038859}{162649650}[/tex]So that's the result.
Expressed as a decimal, it is -0.0063871 approximately.
