Given the following system of equation:
x - y = 10
3x - 2y = 25
Let's determine the solution by elimination:
a.)
x - y = 10
3x - 2y = 25
b.)
(x - y = 10)(-2)
3x - 2y = 25
c.)
-2x + 2y = -20
3x - 2y = 25
x + 0 = 5
x = 5
Therefore, x = 5
Next, let's find y.
Substitute x = 5 in x - y = 10
x - y = 10
5 - y = 10
-y = 10 - 5
-y = 5
-y/-1 = 5/-1
y = -5
Therefore, the solutions are: x = 5 and y = -5 or (5, -5)
