Respuesta :

We have to differentiate f(x).

We can do this as:

[tex]\begin{gathered} f(x)=(5x-5)(6x+1)=30x^2-30x+5x-5=30x^2-25x-5 \\ f\text{'}(x)=30\cdot(2x)-25\cdot(1)-0 \\ f\text{'}(x)=60x-25 \end{gathered}[/tex]

The answer is f'(x)=60x-25.

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