Solution:
Given the equation below;
[tex]e^{0.3x}=0.3[/tex]
Evaluating the expression,
[tex]\begin{gathered} \ln e^{0.3x}=\ln0.3 \\ 0.3x=\ln \left(0.3\right) \\ x=\frac{\ln(0.3)}{0.3} \\ x=-4.01\text{ \lparen two decimal places\rparen} \end{gathered}[/tex]
Hence, the answer is option B
