FaerynL262091 FaerynL262091
  • 25-10-2022
  • Physics
contestada

1. An ordinary light bulb is marked “60A, 120V”, its resistance is ______.

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ZayanaD779899 ZayanaD779899
  • 25-10-2022

In order to calculate the resistance, we can divide the voltage and the current, according to the formula below:

[tex]R=\frac{V}{I}[/tex]

Where R is the resistance (in ohm), V is the voltage (in Volt) and I is the current (in Ampere).

So, using V = 120 V and I = 60 A, we have:

[tex]R=\frac{120}{60}=2\text{ ohms}[/tex]

Therefore the resistance is 2 ohms.

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