Given the equation:
[tex]\sin ^2x(\csc ^2x-1)[/tex]
Using the Pythagorean identities
so,
[tex]\csc ^2x-1=\cot ^2x[/tex]
so, the equation will be:
[tex]\begin{gathered} \sin ^2x\cdot\cot ^2x \\ \\ =\sin ^2x\cdot\frac{\cos ^2x}{\sin ^2x} \\ \\ =\cos ^2x \end{gathered}[/tex]
