Respuesta :

the given equation is

[tex]\begin{gathered} 9m^2+6m+6=5 \\ 9m^2+6m+1=0 \end{gathered}[/tex]

we will calculate

[tex]D=b^2-4ac[/tex]

so

[tex]\begin{gathered} =6^2-4\times9\times1 \\ =36-36 \\ =0 \end{gathered}[/tex]

as D is 0 so it has one real root

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