Given the equation of the parabola:
[tex]y=x^2+6x-12[/tex]
To find the vertex of the parabola,
we will substitute with the value (-b/2a) into the function y
[tex]\begin{gathered} a=1 \\ b=6 \\ c=-12 \\ \\ x=-\frac{b}{2a}=-\frac{6}{2\cdot1}=-3 \\ y=(-3)^2+6\cdot-3-12=9-18-12=-21 \end{gathered}[/tex]
so, the coordiantes of the vertex :
x = -3
y = -21
