Respuesta :

[tex]\begin{gathered} a. \\ \cos \theta=\frac{4}{5} \\ \cos ^2\theta+\text{ }\sin ^2\theta=\text{ 1} \\ \sin ^2\theta=1-\cos ^2\theta \\ \sin ^2\theta=\text{ 1-(}\frac{4}{5})^2 \\ \\ \sin ^2\theta=\text{ 1-}\frac{16}{25} \\ \\ \sin ^2\theta=\text{ }\frac{9}{25} \\ \\ \sin ^{}\theta=\sqrt[]{\text{ }\frac{9}{25}} \\ \\ \sin ^{}\theta=\text{ }\frac{3}{5} \\ \\ \text{The }\sin ^{}\theta\text{ is }\frac{3}{5} \\ \\ b. \\ \text{tan}\theta=\frac{\sin^{}\theta}{\cos\theta} \\ \\ \text{tan}\theta=\frac{3}{5}\text{ }\frac{\cdot}{\cdot}\frac{4}{5}=\frac{3}{4} \\ \\ \text{tha tan }\theta\text{ is }\frac{3}{4} \end{gathered}[/tex]

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