1. Divide the first term of the dividend into the first term of the divisor:
[tex]\frac{6x^2}{2x}=3x[/tex]
2. Multiply the result above by the divisor:
[tex]3x(2x+1)=6x^2+3x[/tex]
3. Subtract the result above from the divident to get a new polynomial:
4. Repeat the process with the new polynomial:
[tex]\begin{gathered} -\frac{16x}{2x}=-8 \\ \\ -8(2x+1)=-16x-8 \end{gathered}[/tex]Then, the result of the division is:[tex]\frac{6x^2-13x+5}{2x+1}=3x-8+\frac{13}{2x+1}[/tex]
