NaOH
M = molarity (mol/L)
[tex]M\text{ = }\frac{mass\text{ of solute}}{\text{molecular mass of solute x volume of solution (L)}}=\frac{moles\text{ of solute}}{\text{volume of solution(L)}}[/tex][tex]M=0.110\text{ }\frac{mol}{L}=\text{ }\frac{moles\text{ of NaOH}}{0.012L}[/tex]12.0 ml = 0.012 L
[tex]\text{moles of NaOH = 0.11 }\frac{mol}{L}x0.012L=1.32x10^{-3\text{ }}moles\text{ of NaOH}[/tex]Answer: moles of NaOH = 1.32x10^-3 moles
[tex]\text{moles NaOH = 1.32x10}^{-3}moles\text{ = 0.00132 moles NaOH}[/tex]