Answer:
B. 1
Explanation:
Given the inequality:
[tex]x^2+5x-6<0[/tex]
To find the critical number, first, change the inequality sign to the equality sign :
[tex]x^2+5x-6=0[/tex]
Next, solve for x:
[tex]\begin{gathered} x^2+6x-x-6=0 \\ x(x+6)-1(x+6)=0 \\ (x-1)(x+6)=0 \\ x-1=0\text{ or }x+6=0 \\ x=1\text{ or }x=-6 \end{gathered}[/tex]
Therefore, from the options, 1 is the critical number.
The correct option is B.
