BashirZ114087 BashirZ114087
  • 25-10-2022
  • Mathematics
contestada

The length of a rectangle is twice its width. If the area of the rectangle is 162in^2, find its perimeter.

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DerrenV208905 DerrenV208905
  • 25-10-2022

We know that the length of a rectangle is twice its width. Then:

The area of a rectangle is the product of its width and length. Then:

[tex]A=2x\cdot x=2x^2[/tex]

Additionally, we know that the area is 162 in². Using the expression above we can obtain the value of x:

[tex]\begin{gathered} 162=2x^2 \\ 81=x^2 \\ x=9\text{ in} \end{gathered}[/tex]

Finally, the perimeter (2P) is just twice the sum of the width and the length of the rectangle:

[tex]2P=2\cdot(2x+x)=6x=6\cdot9=54\text{ in}[/tex]

Ver imagen DerrenV208905
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