a)
We need to find the value of f(-3), that means we need to find the value of the y-coordinate when the x-coordinate is -3
As we can see in the graph
f(-3)=-5
Therefore f(-3) is negative
The answer for this part is NO
b)
if f(x)=0, that means that we are looking for the x-intercepts
x=-2
x=1
x=4
The answer is -2,1,4
c)
We need to know for what values of x f(x)<0
In this case in interval notation
[tex]\lbrack-3,2)\cup(1,4)[/tex]
