Solution -:
By Using Pythagoras theorem-:
We know that,,
(Hypotenuse)²= ( Base )² + ( Perpendicular)²
than,,,, AC²= BC² + AB²
so,,,
[tex]( h) {}^{2} = ({15}^{2} ) + (\ {8}^{2} )[/tex]
[tex]AB = \sqrt{225 + 64} [/tex]
[tex]AB = \sqrt{289} [/tex]
then,,
[tex]AB \: = 17[/tex]
then,,, the value of sin a
[tex] \bold{= \frac{8}{17} }[/tex]
Thus option ( B ) is correct
