The simplified form of the expression as in the task content is; (y-3)/7y.
What is the simplified form of the expression as represented in the task content?
It follows that the expression given in the task content is;
(4y⁴)/(y+3) ÷ (28y⁵)/(y²-9)
= (4y⁴)/(y+3) ÷ (28y⁵)/(y -3) (y+3) {difference of two squares}.
= (4y⁴)/(y+3) × (y -3) (y+3)/(28y⁵)
= (4y⁴/28y⁵) × (y-3)
= (y-3)/7y
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