Answer:
A
Step-by-step explanation:
using the rule of exponents
[tex]\frac{a^{m} }{a^{n} }[/tex] = [tex]a^{(m-n)}[/tex]
to find how many times larger 9 × [tex]10^{7}[/tex] is than 3 × 10³, divide , that is
(9 × [tex]10^{7}[/tex] ) ÷ (3 × 10³)
= [tex]\frac{9}{3}[/tex] × [tex]\frac{10^7}{10^3}[/tex]
= 3 × [tex]10^{(7-3)}[/tex]
= 3 × [tex]10^{4}[/tex]
