Respuesta :

  • LiOH+CaCl_2—»LiCl+Ca(OH)_2

Balanced

Moles of CaCl_2=0.425mol

1 mol CaCl_2 producees 1 mol LiCl

Moles of LiCl

  • 0.425(1)
  • 0.425moles
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The equation is

[tex]\\ \tt{:}\dashrightarrow LiOH+CalCl_2\longrightarrow LiCl+Ca(OH)_2[/tex]

  • This is balanced

1mol of LiCl needs 1 mol CaCl_2

Then

0.425mol of CaCl_2 will produce 0.425mol LiCl

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