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Question

A father is 30years older than his son. In 12years, the man will be three times as old as his son. Find their present ages.
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Solution

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Let the present age of the son be x years
Then father's age will be (x+30) years
Given after 12 years father will be three times as old as his son
Therefore,
(x+12)3=x+30+12
3x+36=x+42
3x−x=42−36
2x=6
x=3
x+30=3+30=33
So, the present age of son is 3 years and present age of the father is 33 years
