marinadawson4915 marinadawson4915
  • 25-05-2022
  • Mathematics
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12250 depreciates by 6% per year how much is the tractor worth after six years

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jdoe0001 jdoe0001
  • 26-05-2022

[tex]\qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{current amount}\\ P=\textit{initial amount}\dotfill &12250\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ t=years\dotfill &6\\ \end{cases} \\\\\\ A=12250(1 - 0.06)^{6}\implies A=12250(0.94)^6\implies A\approx 8450.90[/tex]

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