[tex]~~~~~\dfrac 12 \left(x-\dfrac 34 \right) = \dfrac 5{12}\\\\\\\implies \dfrac{4x-3}4= \dfrac{5 \times 2}{12}\\\\\\\implies 4x-3 = \dfrac{5 \times 2 \times 4}{12}\\\\\\\implies 4x -3=\dfrac{40}{12}\\\\\\\implies 4x -3 = \dfrac{10}3\\\\\\\implies 4x = \dfrac{10}3 +3\\\\\\\implies 4x = \dfrac{19}3\\\\\\\implies x = \dfrac{19}3 \times \dfrac 1 4\\\\\\\implies x = \dfrac{19}{12}[/tex]
