Respuesta :

subtomex0

AB=AOB×r

6π=9AOB

AOB=3π/2

The area of the circular sector is given by;

[tex]a = \frac{ \frac{3\pi}{2} }{2\pi} \times (\pi \: r {}^{2} )[/tex]

[tex]a = \frac{3\pi}{4} \times 81\pi[/tex]

[tex]a = 60.75\pi[/tex]

[tex]a = 190.85 \: cm {}^{2} [/tex]

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