Answer:
[tex]5(x-3)(x-4)[/tex]
Step-by-step explanation:
[tex]5x^2-35x+60[/tex]
Start by factoring out a 5:
[tex]5(x^2-7x+12)[/tex]
We need to find two integers that have a product of 12, and a sum of -7:
(-3)(-4)=12
-3-4=-7
We can split -7x into -3x and -4x
[tex]5(x^2-3x-4x+12)[/tex]
Factor each half separately:
[tex]5[x(x-3)-4(x-3)][/tex]
Since x and -4 are both being multiplied by x-3, we can combine them:
[tex]5(x-3)(x-4)[/tex]
