Answer:
see below
Step-by-step explanation:
[tex]y=-3(x-4)^2+2[/tex]
[tex]x=-3(y-4)^2+2[/tex]
[tex]x-2=-3(y-4)^2[/tex]
[tex]\frac{1}{3}(2-x) =(y-4)^2[/tex]
[tex]\sqrt{\frac{1}{3}(2-x)}=y-4[/tex]
[tex]f^{-1}(x)=\sqrt{ \frac{1}{3}(2-x)}+4[/tex]
