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24-12-2021
Mathematics

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A projectile is thrown upward so that its distance above the ground after t seconds is h = -156 + 510t. What is its maximum height?

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24-12-2021

For the parabola:

h(t) = -at2 + bt, the maximum occurs at -b/2a

For h(t) = -16t2 + 576t that is -576/(-2)(-16), or -576/32, or 18.

The projectile is at its highest point at 18 seconds.

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