franciscochavez7940 franciscochavez7940
  • 25-10-2021
  • Mathematics
contestada

Write the equation of a line perpendicular to the line 2x + 3y = 12 and passes through (9, -2). (fractions go in one box - use lower case letters)

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timothysmith25840 timothysmith25840
  • 25-10-2021

Answer:

Step-by-step explanation:

Write the equation of the line perpendicular to 2x-3y=12 that passes through the point (16,-7)

 

Rewrite the equation as  y = (2/3)x - 4  This has slope 2/3

 

A perpendicular line will have slope -3/2 so the equation of a perpendicuar line is y = -(3/2)x + c where c is a constant found from the fact that the line must go through point (16, -7).

 

-7 = -(3/2).16 + c

c = 24 - 7  

c = 17

 

Hence perpendicular line has equation  y = -(3/2)x + 17

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