lyphuc531 lyphuc531
  • 23-10-2021
  • Mathematics
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2cosx-[tex]\sqrt{2}[/tex]=0

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Аноним Аноним
  • 23-10-2021

[tex]\\ \sf\longmapsto 2cosx-\sqrt{2}=0[/tex]

[tex]\\ \sf\longmapsto 2cosx=\sqrt{2}[/tex]

[tex]\\ \sf\longmapsto cosx=\dfrac{\sqrt{2}}{2}[/tex]

[tex]\\ \sf\longmapsto cosx=\dfrac{1}{\sqrt{2}}[/tex]

[tex]\\ \sf\longmapsto x=cos^{-1}\left(\dfrac{1}{\sqrt{2}}\right)[/tex]

[tex]\\ \sf\longmapsto x=60[/tex]

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